Here we are explaining how to write a java program to find out the duplicate characters in a string.
First, we have to declare the class DC. Then open the main function. Declare the string variables str1 and assign value for it. Declare a character array and convert the string str1 into character. Then by using a nested for loop check any duplicate characters are there. If found then increment the count variable c by one and change the position of the character to '1'.Then we will display the duplicate character by checking the condition if i>0 and ch!='1'.
We can convert a string into a character array by using the method toCharArray(). The syntax of toCharArray() is shown below.
public char[] toCharArray().
It returns a character array. The length of the character array is same as the length of the string.
STEP 1: Declare the class DC with a public modifier.
STEP 2: Open the main() to start the program, Java program execution starts with the main()
STEP 3: Declare the string variable str1 and assign some value to it.
STEP 4: convert the string str1 to an array s[] by using toChaArray() method.
STEP 5: By using a for loop set i=0, check i
STEP 6: set c=1.
STEP 7: By using another for loop set j=i+1,check the condition j
STEP 8: Check if s[i]=s[j] and s[j]!=' '' then incremnet c by one.
STEP 9: Set s[j] to 1. Increment j by one and repeat step 7.
STEP 10: Check if c>1 and s[i]!='1' then display s[i]
STEP 11:Incremnet i by one and repeat step 5.
public class DC {
public static void main(String[] args) {
String str1 = "My name is siril";
int c;
//Convert the string to array
char s[] = str1.toCharArray();
System.out.println("Duplicate characters in the string: ");
for (int i = 0; i < s.length; i++) {
c = 1;
for (int j = i + 1; j < s.length; j++) {
if (s[i] == s[j] && s[i] != ' ') {
c++;
//Set str1[j] to 1
s[j] = '1';
}
}
if (c > 1 && s[i] != '1')
System.out.println(s[i]);
}
}
}
Duplicate characters in the string: i s
