In this program we are checking the number is disarium or not. To check that we have to find the power of each digit of the number according to their position and add those together and if the result is equal to the original number then the number is considered as disarium number. For example, if the entered number is **135** then we calculate **1 ^{1} + 3^{2} + 5^{3}** which is

In this program, we are accepting the value from the user and assigning it to the variable **num**. Then we have to assign value **0** into the variables sum and rem and also assign the length of the number into the variable **size** and assign the value of the variable **num** into the variable n. After that, we have to perform `while`

`loop`

until the condition **'n > 0'** becomes false and in the block of the loop first assign the computed values of **'n % 10'** into the variable **rem**, **'sum + pow(rem, size)'** into the variable **sum** and **'n /10'** into the variable **n** and also decrement the value of the variable **size** and after the completion of the loop we have to check the condition **'sum == num'** if true print the value of the variable as disarium number otherwise as not a disarium number.

**Step 1:** Accept the number from the user into the variable **num**

**Step 2:** Assign value **0** into the variables **sum** and **rem**

**Step 3:** Assign the length of the number into the variable **size**

**Step 4:** Assign the value of the variable **num** into the variable **n**

**Step 5:** Perform sub-steps until the condition **'n > 0'** becomes false

(i) Assign the computed value of **'n % 10'** into the variable **rem**

(ii) Assign the computed value of **'sum + pow(rem, size)'** into the variable **sum**

(iii) Assign the computed integer value of **'n /10'** into the variable **n**

(iv) Decrement the value of the variable **size**

**Step 6:** Check the condition **'sum == num'** if true print the value of the variable as disarium number otherwise as not a disarium number

` ````
<?php
$num = readline("Enter the number");
$rem = 0;
$sum = 0;
$size = strlen($num);
$n = $num;
while ($n > 0) {
$rem = $n % 10;
$sum = $sum + pow($rem, $size);
$n = (int)($n / 10);
$size--;
}
if ($sum == $num)
echo "$num is a disarium number";
else
echo "$num is not a disarium number";
?>
```

Example 1 Enter the number518 518 is a disarium number Example 2 Enter the number143 143 is not a disarium number Example 3 Enter the number89 89 is a disarium number