The int() function helps to convert the given value into an integer number. The result integer value always is in base 10.If we use int() with a custom object, then the object __int__() function will be called.
int(x=0, base=10)# Where x can be Number or string
Takes 2 parameters where the first parameter 'x' default value is 0. And the second parameter 'base' default value is 10, it also can be in 0 (code literal) or 2-36.
| Parameter | Description | Required / Optional |
|---|---|---|
| x | Number or string to be converted to integer object. | Required |
| base | The base of the number in x | Optional |
| Input | Return Value |
|---|---|
| integer object | base as 10 |
| No parameters | returns 0 |
| If base given | in the given base (0, 2, 8, 10, 16) |
# integer
print("int(123) is:", int(123))
# float
print("int(123.23) is:", int(123.23))
# string
print("int('123') is:", int('123'))
Output:
int(123) is: 123
int(123.23) is: 123
int('123') is: 123
# binary 0b or 0B
print("For 1010, int is:", int('1010', 2))
print("For 0b1010, int is:", int('0b1010', 2))
# octal 0o or 0O
print("For 12, int is:", int('12', 8))
print("For 0o12, int is:", int('0o12', 8))
# hexadecimal
print("For A, int is:", int('A', 16))
print("For 0xA, int is:", int('0xA', 16))
Output:
For 1010, int is: 10 For 0b1010, int is: 10 For 12, int is: 10 For 0o12, int is: 10 For A, int is: 10 For 0xA, int is: 10
class Person:
age = 23
def __index__(self):
return self.age
def __int__(self):
return self.age
pers
print('int(person) is:', int(person))
Output:
int(person) is: 23
Note:Internally, int() method calls an object's __int__() method.Both these methods should return the same value.The case is that older versions of Python uses __int__(), while newer uses __index__() method.
